C# OpenFileDialog

C# OpenFileDialog

 

 

OpenFileDialog dlg = new OpenFileDialog();
dlg.Multiselect = true;
 
if (dlg.ShowDialog() == true)
{
    var result = await Upload(new List<string>(dlg.SafeFileNames), new List<string>(dlg.FileNames));
 
    MessageBox.Show(result ? "성공" : "실패");
}